sub x( --> Hash) { my %h = A => 'a' }
1) '-->' in the signature is the best way to provide information to the
compiler about what the subroutine should return
2) 'returns' in the declaration (not the part in the block) used to be
used, but for some arcane reason that I never really understood, it is
deprecated.
3) 'Hash' or 'Associative'. These all refer to roles that a hash will 'do'.
4) A block (that is the { ... } bit) will always 'return' the last
expression evaluated. So there is no need for the 'return %h' in your
code. 'return ...' is only needed if you have some logic where the
block can exit in several places, not just the last expression.
5) To specify an 'array', you can use 'sub x( --> Array) { my @a = 1..* }'
6) HOWEVER, you really do need to read the documentation about
Sequences, lists and arrays.
Richard
On 21/01/2020 04:09, ToddAndMargo via perl6-users wrote:
On 2020-01-20 19:55, ToddAndMargo via perl6-users wrote:
Hi All,
What is the proper way to state that I am returning a
hash from a sub? `sub x() returns % {}`
And an array? `sub x() returns @ {}`
Many thanks,
-T
I think this is it:
> sub x() returns Associative { my %h= A=>"a"; return %h}
&x
> x
{A => a}
> sub y() returns Array { my @a=(1,2,3,2,1) ; return @a}
&y
> y
[1 2 3 2 1]
Am I too high up the food chain with Associative and Array?
-T
