If you don't want any results with less than 3 lines:
for lines.rotor(3) -> @a {
dd @a;
}
If you *do* want results with 3 lines:
for lines.rotor(3, :partial) -> @a {
dd @a;
}
Alternately as shown below:
for lines -> $x, $y?, $z? {
dd $x, $y, $z
}
Note the question marks to make $y and $z optional: otherwise the last
iteration will throw an exception if there were less than 3 lines left.
> On 23 Nov 2019, at 12:30, Raymond Dresens <raymond.dres...@gmail.com> wrote:
>
> Hello,
>
> This seems possible:
>
> > my @x = (1, 2, 3, 4, 8, 16, 32, 64, 128);
> [1 2 3 4 8 16 32 64 128]
>
> Then:
>
> > for @x -> $x, $y, $z { $x.say }
> 1
> 4
> 32
>
> And:
>
> > for @x -> $x, Any, Any { $x.say }
> 1
> 4
> 32
>
> ...assigning to 'Any' seems to 'just work'. Assigning to 'Nil' didn't work,
> however.
>
> Is this what you are looking for?
>
> Perhaps there's a better way for doing this? If so, I'd like to know too :)
>
> Regards,
>
> Raymond.
>
> On Sat, 23 Nov 2019 at 07:00, ToddAndMargo via perl6-users
> <perl6-us...@perl.org> wrote:
> Hi All,
>
> In a "for" loop, what is the syntax for "by 3"?
>
> for @x.lines by 3
>
> In other words, every third line.
>
> Many thanks,
> -T
