In

     {l for l in L}

The reason it is in `{}` is to create a Set from iterating over `L`.

> In Python, the set-builder's braces are replaced with square brackets, 
> parentheses, or curly braces, giving list, generator, and set objects, 
> respectively.

So in Python:

    [ l for l in L ]     gives a list
    ( l for l in L )     gives a generator
    { l for l in L }     gives a set

In Perl6 those would most likely be written as:

    L.List   or   L.Array   or   L.list
    L.Seq
    L.Set

---

The way to do that is

    my \L = ((1..10) xx 3).flat.pick(*).list;

    set( L ) # A
    L.Set # B

    my %set is SetHash;
    { ++%set{$_} for L }  # C

    # D
    do {
        # add the {} syntax to create a Set (lexically)
        my sub circumfix:«{ }» ( \L ) { L.Set };

        { $_ for L } # <--
    }

Something that seems similar to me is `unique`

    .say for L.unique;

By that I mean, some places where you would use a Set, it makes sense
to use `.unique` instead

---

As for `{(k, x) for k in K for x in X if P(x)}`

The easiest one to directly translate appears to be the Scala one

    my \K = 1..10;
    my \X = 5..15;

    # for (k <- K; x <- X if P(x)) yield (k,x)
    Set.new: gather {
        for K -> \k {
            for X -> \x {
                if P(x) {
                    take (k,x);
                }
            }
        }
    }

Other ways:

    Set.new: (K X[,] X).grep: -> ( \k, \x ) { P(x) }

    Set.new: K X[,] X.grep: &P

    Set.new: K X[,] X.grep: &P

    Set.new: ( -> ( \k, \x ) { (k,x) if P(x) } for K X[,] X )

    Set.new: ( -> \x { |(-> \k { (k,x) if P x } for K) } for X)

On Sun, Feb 10, 2019 at 10:26 AM mimosinnet <mimosin...@gmail.com> wrote:
>
> Hi all,
>
> I wonder what would be the Perl notation for 'set-builders', as exposed
> in this wikipedia article:
>
> https://en.wikipedia.org/wiki/Set-builder_notation#Parallels_in_programming_languages
>
> This is the Python notation:
>
> Example 1: {l for l in L}
> Example 2: {(k, x) for k in K for x in X if P(x)}
>
> This is another example in Python:
>
> s = {v for v in 'ABCDABCD' if v not in 'CB'}
>
> https://en.wikipedia.org/wiki/List_comprehension#Similar_constructs
>
> I have been playing with the code below. Nevertheless, I am unsure on
> how to use the code to define a set.
>
> Cheers!
>
> <--- Code
> #!/usr/bin/env perl6
>
> my @L = 1 .. 10;
> my @K = 1 .. 10;
> my @X = 5 .. 15;
>
> say "Example 1:";
> for @L -> $l {
>   print "$l " if $l ∈ @L;
> }
>
> say "\nExample 2:";
> for @K -> $k { for @X -> $x {
>     print "($k, $x), " if ($k ∈ @K and $x ∈ @X and $x < 8);
> }}
> <---
>
> --
> (≧∇≦) Mimosinnet (Linux User: #463211)

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