The `=` infix operator is a meta operator.
That means it takes an infix operator as a sort of "argument".
There is no `+=` operator, it is just the `=` operator combined with
the `+` operator.
$a += 2;
$a [+]= 2; # more explicitly take the + operator as an argument to
the = operator
So if you want to know how to use a similar operator to `+=`, start
with the infix operator you want, and add `=`
$i = $i +< 0x01;
$i [+<]= 0x01;
$i +<= 0x01;
On Fri, Feb 8, 2019 at 12:20 AM Todd Chester via perl6-users
<perl6-us...@perl.org> wrote:
>
> Hi All,
>
> Is this the only way to shift left?
>
> $i = $i +< 0x01
>
> $ p6 'my int32 $i=0x00005DAE; say $i.base(0x10); $i = $i +< 0x01; say
> $i.base(0x10);'
>
> 5DAE
> BB5C
>
>
> Does we have any of those fancy += ~= ways of doing it?
>
> Many thanks,
> -T
