$a<a b> is short for $a{'a','b'}
This also happens in string literals
my $a = { a => 1, b => 2 };
say "$a<a b>"; # 1 2
say "$a{'a','b'}"; # 1 2
A simple way to stop this is to add a backslash
my $a = 'b'
say "$a\<a b>"; # b<a b>
You can also call methods on variables in string literals, as long as
you use parentheses.
my $a = Date.today;
say "$a.year()-$a.month()-$a.day()"; # 2019-1-11
(Note that Date has a .yyyy-mm-dd() method)
---
Looking at the message you just added:
Perl 6 has a Version type.
my $a = Version.new("12.3.4.1");
my $b = Version.new("111.3.4.1");
say $a before $b; # True
Also there is syntax for creating a Version literal
my $a = v12.3.4.1;
my $b = v111.3.4.1;
say $a before $b; # True
There are useful methods on Versions
my $a = v12.3.4.1;
say $a.parts.perl; # (12, 3, 4, 1)
On Fri, Jan 11, 2019 at 8:12 PM ToddAndMargo via perl6-users
<perl6-us...@perl.org> wrote:
>
> On 1/11/19 5:08 PM, ToddAndMargo via perl6-users wrote:
> > Hi All,
> >
> > Now what am I doing wrong? I need to convert the value in a
> > hash to a string:
> >
> > $ p6 'my $x = "acme"; my Str $y; my %Vendors = ( acme => ContactName =>
> > "Larry" ); $y= %Vendors<ContactName>; say $y;'
> > Type check failed in assignment to $y; expected Str but got Any (Any)
> > in block <unit> at -e line 1
> >
> >
> > $ p6 'my $x = "acme"; my Str $y; my %Vendors = ( acme => ContactName =>
> > "Larry" ); $y= %Vendors<ContactName>.Str; say $y;'
> > Use of uninitialized value of type Any in string context.
> > Methods .^name, .perl, .gist, or .say can be used to stringify it to
> > something meaningful.
> > in block <unit> at -e line 1
> >
> >
> > Many thanks,
> > -T
>
> Figured out my booboo. I had to change from
>
> $PartsStr =
> "Hi $Manager,<br><br>" ~
> "Account Number: <b>$AccountNo</b><br><br>" ~
>
> to
>
> $PartsStr =
> "Hi " ~ $Manager ~ ",<br><br>" ~
> "Account Number: <b>" ~ $AccountNo ~ "</b><br><br>" ~
