.contains tests whether its invocant, treated as a string, contains its
argument, treated as a string.
The argument you've given to .contains is:
"b" && not "q".
That's not a string.
Here's one option:
my$x="abcd"; if $x.contains("b") && not $x.contains("q") {say "y"}else{say
"n"};
On Tue, Dec 18, 2018 at 10:49 PM ToddAndMargo via perl6-users <
perl6-us...@perl.org> wrote:
> Hi All,
>
> Where is my booboo?
>
> $ p6 'my$x="abcd"; if $x.contains("b" && not "q") {say "y"}else{say "n"};'
>
> n
>
>
> In the mean time, I will ue
> if $x.contains("b") && not $x.contains( "q" )
>
>
> Many thanks,
> -T
>
> --
> ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
> When you say, "I wrote a program that
> crashed Windows," people just stare at
> you blankly and say, "Hey, I got those
> with the system, for free."
> -- Linus Torvalds
> ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
>
