On 10/8/18 4:20 AM, ToddAndMargo via perl6-users wrote:
On 10/8/18 4:14 AM, Curt Tilmes wrote:
On Mon, Oct 8, 2018 at 7:06 AM ToddAndMargo via perl6-users
<perl6-us...@perl.org <mailto:perl6-us...@perl.org>> wrote:
$ p6 'my $fh=open "/home/linuxutil/To", :r; my Buf $f = $fh.read(
10 );
$fh.close; dd $f; for $f[0..*] -> $Byte { if $Byte == 0b00 {say
"Binary"; last;}else{say $Byte}}'
Buf[uint8] $f = Buf[uint8].new(87,111,114,100,80,114,111,0,0,0)
87
111
114
100
80
114
111
Binary
To get the above to work, I had to say `$f[0..*]`. If I used
`$f`, it made one loop over the entire variable.
$ p6 'my $fh=open "/home/linuxutil/To", :r; my Buf $f = $fh.read(
10 );
$fh.close; dd $f; for $f -> $Byte { if $Byte == 0b00 {say "Binary";
last;}else{say $Byte}}'
Buf[uint8] $f = Buf[uint8].new(87,111,114,100,80,114,111,0,0,0)
Buf[uint8]:0x<57 6f 72 64 50 72 6f 00 00 00>
I never have to say `$str[0..*]` when looping over a string. Why?
How do you loop over a string? Doesn't 'for $str' just also run the
loop once?
Your $f is one thing (it is a scalar), so for $f will just do one thing.
You can also use for $f.list or for @$f
Curt
$ p6 'my $x="a\nb\nc\nd"; for split( "\n", $x ) -> $Line { say $Line };'
a
b
c
d
Or an array:
$ p6 'my @x=<1 b 2 c>; for @x -> $Line { say $Line };'
1
b
2
c
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