On Wed, May 16, 2018 at 9:05 PM, Todd Chester <toddandma...@zoho.com
<mailto:toddandma...@zoho.com>> wrote:
On 05/16/2018 07:58 AM, Timo Paulssen wrote:
On 16/05/18 00:10, ToddAndMargo wrote:
What would the syntax be for d..z, but not g or m?
You can subtract [gm] from [d..z] like this:
say "c" ~~ /<[d..z]-[gm]>/;
say "d" ~~ /<[d..z]-[gm]>/;
say "f" ~~ /<[d..z]-[gm]>/;
say "g" ~~ /<[d..z]-[gm]>/;
Something is wrong:
$ p6 'if "dgm" ~~ /<[d..z]-[gm]>/ {say "yes"}else{say "no"};'
yes
I want it to fail if it find g or m
:'(
$ alias p6
alias p6='perl6 -e'
On 05/16/2018 06:10 PM, Brandon Allbery wrote:
> You need to be more careful with regexes (any regexes). Your character
> class matches if any character in the string matches, so 'd' satisfies
> it and the rest of the string is ignored. If you want to ensure *no*
> character matches, then say so:
>
> pyanfar Z$ 6 'if "dgm" ~~ /^<[d..z]-[gm]>*$/ {say "y"} else {say "n"}'
> n
>
>
`^` for start at the beginning and `*$` for keep going all the
way to the end.
Now I understand. Thank you!
$ p6 'if "dgm" ~~ /^<[d..z]-[gm]>*$/ {say "y"} else {say "n"}'
n
$ p6 'if "def" ~~ /^<[d..z]-[gm]>*$/ {say "y"} else {say "n"}'
y
$ p6 'if "abc" ~~ /^<[d..z]-[gm]>*$/ {say "y"} else {say "n"}'
n
