I disagree; this is not Haskell, if I do something like that then I expect %h2 to retain its original value while the RHS is being evaluated.
On Mon, Feb 27, 2017 at 4:35 AM, Elizabeth Mattijsen <l...@dijkmat.nl> wrote: > FWIW, this feels like a DIHWIDT case > > > On 27 Feb 2017, at 00:55, Aleks-Daniel Jakimenko-Aleksejev (via RT) < > perl6-bugs-follo...@perl.org> wrote: > > > > # New Ticket Created by Aleks-Daniel Jakimenko-Aleksejev > > # Please include the string: [perl #130870] > > # in the subject line of all future correspondence about this issue. > > # <URL: https://rt.perl.org/Ticket/Display.html?id=130870 > > > > > > > Code: > > my %h1 = <1 a 2 b>; > > my %h2 = <3 c 4 d>; > > my %h3 = <5 e 6 f>; > > %h2 = %h1, %h2, %h3; > > say %h2 > > > > Result: > > {1 => a, 2 => b, 5 => e, 6 => f} > > > > > > Notice that it has everything except for elements of %h2. > > > > If this behavior is correct, then it should throw a warning. But I'd > argue that it should work exactly the same way as if it was an assignment > to a different hash. > -- brandon s allbery kf8nh sine nomine associates allber...@gmail.com ballb...@sinenomine.net unix, openafs, kerberos, infrastructure, xmonad http://sinenomine.net
