Re: [perl #130540] [BUG] || && and or cannot be "overloaded"

[Fernando Oliveira]

But should those 2 forms behave differently?

20:40 <SmokeMachine> m: multi infix:<||>(42, 42) {"OK"}; say infix:<||>(42, 
42); say 42 || 42
20:40 <camelia> rakudo-moar 8f3476: OUTPUT«OK␤42␤»

Enviado do meu iPhone

> Em 11 de jan de 2017, às 20:20, jn...@jnthn.net via RT 
> <perl6-bugs-follo...@perl.org> escreveu:
> 
>> On Tue, 10 Jan 2017 17:59:05 -0800, c...@zoffix.com wrote:
>>> On Tue, 10 Jan 2017 16:23:18 -0800, fernandocor...@gmail.com wrote:
>>> If I write another || operator it will continue to use the original
>>> version.
>>> 
>>> https://irclog.perlgeek.de/perl6/2017-01-10#i_13895823
>>> <https://irclog.perlgeek.de/perl6/2017-01-10#i_13895823>
>> 
>> To save other readers sifting through the chan log... Even an only sub
>> doesn't take root:
>> 
>> <Zoffix> m: sub infix:<||> ($, $) {"hi"}; say 42 || 55
>> <camelia> rakudo-moar 9a11ea: OUTPUT«42␤»
>> 
>> This applies to &&, and, or, and I'd guess any shortcurcuiting
>> operator.
> 
> These are special compiler forms that receive special code-gen, due to their 
> shortcircuiting nature, and so do not result in sub calls. Thus there's no 
> sub to override.
>