As a follow-up: The following code works as expected:
$ perl6-j -e 'my @a; @a[0;1] = "foo"; @a[0;0] = "bar"; say @a.perl' [["bar", "foo"],]
Christian Bartolomaeus via RT Tue, 07 Jun 2016 13:47:23 -0700
As a follow-up: The following code works as expected:
$ perl6-j -e 'my @a; @a[0;1] = "foo"; @a[0;0] = "bar"; say @a.perl' [["bar", "foo"],]