Probably not the best but a working solution is to split the string using 
"split", find out wether there are to much fields, consider they are 
two-or-more-word names, join the corresponding name-fields with a space and the 
overall with tabs.
 
Dietmar
 
--- snip ---
 
I'm fairly good at using regexes to find things, but using them to 
*replace* things is something I find quite difficult.  I have a text file 
with lines like this:

<snip>

1 (1) DAVENPORT, LINDSAY 3380.00 16 .00 49.00 USA .00
2 (2) CLIJSTERS, KIM 3206.00 17 .00 .00 BEL .00
[...]
28 (28) MOLIK, ALICIA 671.00 15 .00 195.00 AUS .00
29 (33) MEDINA GARRIGUES, ANABEL 660.75 27 30.00 10.00 ESP 2.00
30 (35) KOUKALOVA, KLARA 660.75 23 16.00 20.00 CZE 2.00

</snip>

that I want to turn into a tab-delimited file.  Unfortunately, I can't 
simply turn all spaces into tabs: note that there are people with two-word 
surnames.  However, I'm having difficulty coming up with any ideas on how 
to find information on either side of a space, and changing that into 
something plus a tab.  I tried the following to deal with the country 
codes:

while (<FILEFROM>) {
  chomp;
  if ($_ =~/\d\s[A-Z]{3}\s/) {
  $_ = s/$1/$1\t/g;
  }
  print FILETO "$_\n";
}

But all I got was a file with a bunch of lines of 1's.  I tried escaping 
the $'s, figuring it wouldn't help, and it didn't: I ended up with an 
empty file.  I also tried putting () around each of the $'s, and that gave 
me an even odder file, with each line containing a two-digit number, with 
no relationship I can spot between the numbers and the country codes: USA 
produces 54, 51, and 52 the first three times it's matched, while RUS 
produces 50, 54, 54, and 56 the first four times it's matched.

I've tried reading perlre, and it's given me no help.  I don't know where 
to begin.

--
Ted Schuerzinger, [EMAIL PROTECTED]

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