[EMAIL PROTECTED] (Chris Wagner) writes:

> At 10:52 AM 12/1/2005 -0500, Ted Schuerzinger wrote:
> >You weren't expecting *fewer* duplicates, were you?
> 
> Well actually, among numbers out to 12 decimal places, yes.  I'ld say there
> should be no duplicates until the number of iterations gets to some
> significant proportion of the combinations.  The combinations in this case
> are 10^12.  I tried 10^5 times.  *Plenty* of headroom there for non 
> duplicates.

Check this link http://en.wikipedia.org/wiki/Birthday_paradox

Regards,
Gisle
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