On Tue, 06 Sep 2005, Sisyphus wrote: "Randy Kobes" wrote:
> I'm still puzzled by that backslash-escape issue, however:
>
> D:\pscrpt>type try.pl
>
> use warnings;
> $z1 = "hello\tworld";
> print $z1, "\n";
> $z2 = "hello\\tworld";
> print $z2, "\n";
> system("rmdir $z2");
>
> D:\pscrpt>perl try.pl
> hello world
> hello\tworld
> rmdir: `hello\\tworld': No such file or directory
>
> D:\pscrpt>
>
> (That's still using the MSYS/bin/rmdir.exe.)
It is rmdir.exe that doubles the backslash before printing it. Just run
rmdir.exe foo\bar
and it will print
rmdir.exe: `foo\\bar': No such file or directory
or
rmdir.exe foo^Abar
(the ^A should be a single Control-A, not 2 separate characters)
prints
rmdir.exe: `foo\001bar': No such file or directory
using the octal notation for ^A
Cheers,
-Jan
> I *think* I understand. When print() receives the argument $z2, it receives
> "hello\\tworld" - and it's the print() function that decides that the first
> backslash escapes the second. When rmdir receives the argument $z2, it also
> receives "hello\\tworld", but it doesn't recognize the backslash as an
> escape and treats it literally. Is that right ?
>
> Up until now, I've always thought that when print() receives the argument
> $z2, it actually receives "hello\tworld" as its argument and prints
> (literally) that. I guess that assumption is (and always was) wrong. If that
> assumption were correct, then we'd have to accept that the $z2 that print()
> receives is different to the $z2 that rmdir receives - and I find it
> difficult to reconcile such a difference.
>
> Cheers,
> Rob
>
>
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