I'm sort of a newbie at interpreting the .f, but I am on a bit of a short leash
so I have a question on some of the workloads and how the loops work...
My goal is to use about 2TB of space I have sitting around ;-) But I have been
blowing WAY over my 2TB....
In a workload like bringover.f, copied below for convenience, is the result of
something like:
nthreads=40
nfiles=1000
filesize=1g
going to be (40*1000*1g) = 40TB?
or is it 40 threads working to create 1000*1g files, so 1TB?
I have a feeling the 40 threads will end up with 40 threads doing 1000 1g
files...based on the way the process is defined...
Any help would be GREATLY appreciated....
define fileset
name=srcfiles,path=$dir,size=$filesize,entries=$nfiles,dirwidth=$dirwidth,prealloc
define fileset
name=destfiles,path=$dir,size=$filesize,entries=$nfiles,dirwidth=$dirwidth
define process name=filereader,instances=1
{
thread name=filereaderthread,memsize=10m,instances=$nthreads
{
flowop openfile name=openfile1,filesetname=srcfiles,fd=1
flowop readwholefile name=readfile1,fd=1
flowop createfile name=createfile2,filesetname=destfiles,fd=2
flowop writewholefile name=writefile2,filesetname=destfiles,fd=2,srcfd=1
flowop closefile name=closefile1,fd=1
flowop closefile name=closefile2,fd=2
}
}
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