I suppose the list is getting tired of this, so via direct e-mail. (Oops!
apparently, your ISP has my ISP blocked, so posting to the list after all).

I am going to have to do some re-research to figure out exactly how I came
to the original conclusions. Which means a trip to the library. The problem
being that there are almost as many formulas for DOF on the internet as
there are internet sites. I need to go back to a basic optical physics book.
In other words now I am confused. Thinking did not used to confuse me
<SIGH>.

See other comments inline:

Ciao,
Graywolf
http://pages.prodigy.net/graywolfphoto


----- Original Message -----
From: "Mike Ignatiev" <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Friday, July 25, 2003 3:17 PM
Subject: Re: Shallow DOF with 6X7 lenses


> I think this is a really good version of the formula,
> especially, if you write it as
> Dn = h/(h+l), Df = h/(h-l) when h>l

Dn = hs/(h+s), Df = hs/(h-s)
Is what that book gives. What would you get if h>1? And, why would you want
to focus beyond infinity?

>
> However, in the definition of what h (hyperfocal distance is) the "1000"
factor should really depend on the final enlargement. Do you insist that h
would be
> the same for 4x6 print and 40x60 alike?
>
> One (also approximate) definition of h is
>
> h = d*f/c, where c -- COC, f -- focal length,
>                  d -- actual aperture diameter.
> Your "1000" means f/c = 1000.
> This is interesting, and it means that as you change
> the film format (say, double both f and c), as long as
> you keep the enlargments of the same size, the hyperfocal distance does
not change. And neither does
> DOF.

Yes! Or, your enlargement is viewed at a distance where the perspective
matchs that of the original scene.

>
> Btw, your formula does not prove your point --
> you express it through diameter and distance-to-
> subject. Not magnification and COC <G>.
>

No, becomes a fixed value, because it is the same for the final print. The
formula is somewhat specialized.

BTW, I think now precive why the formula Mark quoted did not work for me. I
was trying to use it as a general formula and it is specific to
magnifications near to 1. But, why did I get values that seemed correct for
farther distances when I used aperture rather than f-stop? I shall have to
run some numbers, and see if I can figure that out. I wish I could find the
book that gave that formula (or what I remember being the same formula), but
I probably do not have it anymore. I am sure it was a general photography
book, not one for close-up photography though.


> But of course, all these things are related
> geometrically. Yes, we kids do know it all <VBG>
>

Or, at least your math skills are fresher. I will admit, that it gets harder
as I age, and use them less an less <NSVBG>. But, I do good for a 10th grade
dropout.



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