Alina Friedrichsen wrote:
> Hello!
>
>> well I doublechecked it .. and while you are right on the checked input, I
>> am sure that
>>
>> if [ -z "=" ] ...
>>
>> shouldn't throw an error .. I also tried simple quotes (')
>
> Yes, only one expression is no Problem in all shell implementations I have
> tested.
you are right here .. I missed that
if [ ! -z "$do_login" ] && [ "$user" == 'foo' -a "$password" == 'bar' ]; then
works, while
if [ ! -z "$do_login" -a "$user" == 'foo' -a "$password" == 'bar' ]; then
throws the error if do_login='='
>> @Alina: Do you have reason to believe this isn't bug? If yes, why.
>
> Whats isn't a bug? It's a design error. You can't implement a shell
> interpreter, that is compatible with the current syntax and don't have the
> Problem, that you can inject a expression with the value argument. It's like
> strcpy() in C.
>
Sorry I only see that test obviously handles one and the same situation
different, or better dies with a syntax error in one case. I am sure this is
not supposed to happen.
.. bud
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