Hi,
On Thu, Mar 18, 2010 at 01:14:22PM +0100, Jan Just Keijser wrote:
> took me a while to figure this one out:
> the openvpn gui codes sets an 'exit event' (using a win32 API call
> CreateEvent) before starting the actual openvpn process; when the user
> chooses 'disconnect' this 'exit event' is triggered, which causes the
> process to be terminated (using the appropriate win32 signal).
Huh, scary stuff.
How would that win32 signal be delivered to the openvpn.exe process? Will
it just receive a unix-like signal "SIGTERM"? Or does it have to poll
some sort of Windows event queue?
BTW: I just discovered that this is not limited to the openvpn.exe I
built *on* windows, but that my linux-mingw crosscompiled openvpn.exe
does this as well now, and so does the original OpenVPN-provided 2.1.1
binary(!). "Something weird happened to this machine", and I don't
understand what it is.
> The question now becomes: what does openvpn do when it receives a
> terminate signal? actually, is there a signal being sent to the server
> to say "client X is disconnecting" ?
Nothing whatsoever visible in the logs. The last entry in the log (verb 5)
is after successful startup:
"Initialization Sequence Complete"
... and then when pressing <disconnect>, nothing whatsoever happens.
The OpenVPN connection stays alive and healthy(!), packets continue to
get forwarded, just the signal delivery fails.
(If I increase the log verbosity to "verb 9", lots of stuff is going
on, but nothing in there that gives any indication of signals being
received)
gert
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