On Mon, Aug 29, 2016 at 3:16 PM, Steven Hardy <sha...@redhat.com> wrote: > On Mon, Aug 29, 2016 at 07:07:09AM +0200, Thomas Herve wrote: >> dict($.groupBy($.keys().toList()[0], $.values().toList()[0][0])) >> >> ought to work, I believe? > > So, as it turns out, my example above was bad, and groupBy only works if > you have a list of maps with exactly one key, we actually need this: > > # Example of tripleo format > # We need an output of > # "gnocchi_metricd_node_names": ["overcloud-controller-0"] > # "tripleo_packages_node_names": ["overcloud-controller-0", > "overcloud-compute-0"] > # "nova_compute_node_names": ["overcloud-compute-0"] > debug_tripleo: > value: > yaql: > expression: dict($.data.l.groupBy($.keys().toList()[0], > $.values().toList()[0][0])) > data: > l: > - "gnocchi_metricd_node_names": ["overcloud-controller-0"] > "tripleo_packages_node_names": ["overcloud-controller-0"] > - "nova_compute_node_names": ["overcloud-compute-0"] > "tripleo_packages_node_names": ["overcloud-compute-0"] > > So, I'm back to wondering how we make the intermediate assignement of > tripleo_packages_node_names
Well I didn't know all the constraints :). $.selectMany($.items()).groupBy($[0], $[1][0]) is another attempt. It won't work if you have more than one value per key in the original data, but I think it will handle multiple keys. -- Thomas __________________________________________________________________________ OpenStack Development Mailing List (not for usage questions) Unsubscribe: openstack-dev-requ...@lists.openstack.org?subject:unsubscribe http://lists.openstack.org/cgi-bin/mailman/listinfo/openstack-dev
