https://stackoverflow.com/questions/6429494/undefined-symbols-for-architecture-armv7
Look at common cause 3 in the first answer. These are the undefined symbols:
"_ENGINE_load_builtin_engines", referenced from:
_libssh2_init in global.c.o
__libssh2_init_if_needed in global.c.o
"_ENGINE_register_all_complete", referenced from:
_libssh2_init in global.c.o
__libssh2_init_if_needed in global.c.o
presumably you didn't recompile them for iOS.
Teja Prabhu
On Thu, May 9, 2019 at 12:11 AM rollas...@gmail.com <rollas...@gmail.com>
wrote:
> Hello.
>
> I have built libssh2 with openssl in windows (MVC 2017), linux (GCC >6),
> mac (clang 8 - 10), android (NDK19 / API 21-24 / clang) successfully.
> Now I am stuck trying to build it for iOS. The error I get is about an
> undefined symbol as folows
>
> ld: warning: -headerpad_max_install_names is ignored when used with
> -bitcode_bundle (Xcode setting ENABLE_BITCODE=YES)
> undefined symbols for architecture armv7:
> "_ENGINE_load_builtin_engines", referenced from:
> _libssh2_init in global.c.o
> __libssh2_init_if_needed in global.c.o
> "_ENGINE_register_all_complete", referenced from:
> _libssh2_init in global.c.o
> __libssh2_init_if_needed in global.c.o
> ld: symbol(s) not found for architecture armv7
> clang: error: linker command failed with exit code 1 (use -v to see
> invocation)
>
> From what I understand, the problem is that the static lib is not
> including a symbol?
>
> I am using XCode 10.2.1 and the command I used to build OpenSSL is
>
> ./Configure iphoneos-cross
> -lsysroot/Applications/Xcode.app/Contents/Developer/Platforms/iPhoneOS.platform/Developer/SDKs/iPhoneOS12.2.sdk
>
> -mios-version-min=10.0 -fembed-bitcode -O3
> --sysroot=/Application/Xcode.app/Contents/Developer/Platforms/iPhoneOS.platform/Developer/SDKs/iPhoneOS12.2.sdk
>
> -fPIC --with-zlib-include=/Users/roll/sdks/zlib/include
> --with-zlib-lib=/Users/roll/sdks/zlib/lib
>
> the build process ends without error and a libcrypto.a and libssl.a
> files are created.
>
> Can anybody point me what am I doing wrong or misunderstanding?
>
> Thanks in advance.
>
>
