On 5/3/2013 4:57 AM, Tom marchand wrote:
Good eye but that's not it. The code below should read BN_free(Res).
Thanks.
On May 2, 2013, at 10:42 PM, Jeremy Farrell wrote:
From: Tom marchand [mailto:tpmarch...@gmail.com]
Sent: Friday, May 03, 2013 2:55 AM
I am using the following code to create a temporary BIGNUM to hold
the result of multiplication:
BIGNUM *Res;
while(!Done)
{
Res=BN_new();
BN_init(Res);
BN_mul(Res,A,B,Ctx);
BN_free();
}
This code works with the exception that BN_free() is not releasing the
memory allocated to Res. I already have a workaround but I am
wondering why the memory isn't being released. In production the code
runs for hours and is causing a significant memory leak. I am I
misusing BN_new and BN_free? The code is running on OSX 10.5.8,
Openssl 0.9.7l. I get the same result with OpenSSL 1.0.1e.
BN_free(Res); ???
Remove the call to BN_init(Res).
BN_new() sets a flag in Res that says that BN_free(Res) should free
both the digit buffer at Res->d and Res itself.
BN_Init() sets the flag that says that BN_free(Res) should free only
Res->d.
The intended usage is EITHER:
void foo(const BIGNUM* A, const BIGNUM* B)
{
BIGNUM *Res;
BN_CTX *Ctx = BN_CTX_new();
while(!Done)
{
Res=BN_new();
BN_mul(Res,A,B,Ctx);
BN_free_clear(Res);
}
BN_CTX_free(Ctx)
}
OR
void bar(const BIGNUM* A, const BIGNUM* B)
{
BIGNUM Res;
BN_CTX Ctx;
BN_CTX_init(&Ctx);
while(!Done)
{
BN_init(&Res);
BN_mul(&Res,A,B,&Ctx);
BN_free_clear(&Res);
}
BN_CTX_free(&Ctx)
}
The choice between the two styles is a matter of optimization specific
to the compiler you use and the actual variable lifetimes in you
application.
Enjoy
Jakob
--
Jakob Bohm, CIO, Partner, WiseMo A/S. http://www.wisemo.com
Transformervej 29, 2730 Herlev, Denmark. Direct +45 31 13 16 10
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