Hello I'm having a basic issue encoding a custom object. I would like the binary output of a new object I've created to appear in DER encoded output as the following TLV
0x5F20 0x08 [8 bytes of value] I think this is implicit,application specific and primitive, so I have the following new definitions #define ASN1_EX_TYPE(ASN1_TFLG_APPLICATION_IMPLICIT, tag, stname, field, type)ASN1_IMPLICIT_APPLICATION(stname, field, type, tag) \#defineASN1_TFLG_APPLICATION_IMPLICIT ASN1_TFLG_IMPTAG|ASN1_TFLG_APPLICATION and I choose to declare my object as an ASN1_BIT_STRING like this ASN1_IMPLICIT_APPLICATION(CUSTOMCERT I have checked that the length of the populated bit string internally is 8. The encoder/decoder and ASN1Parse run through OK. However the binary result I actually get in DER format is this 0x5F20 0x09 0x03 [8 bytes of value] So I have an extra '0x03' which is presumably a V_ASN1_BIT_STRING tag, which I don't want. This pushes the length from 8 to 9 So how can I lose this extra encoded byte without confusing my encoder or decoder ? I don't need to use an ASN1_BIT_STRING - anything that lets me populate with 8 arbitrary bytes is fine. There may be a better way to achieve the 0x5F20 tag than my guesses above. thanks in advance John_CINF, subject_customcert_id, ASN1_BIT_STRING, 0x20), ______________________________________________________________________ OpenSSL Project http://www.openssl.org User Support Mailing List openssl-users@openssl.org Automated List Manager majord...@openssl.org
