Hi,
I'm a newbie when it comes to RSA, the last time I learned it was in school
over 7 years ago in one lecture.
Maybe I'm missing something but I will try to explain my problem again.

A former co worker generated a public and private key for our group. (I
think he used PGP but not sure).
So I have the 2 .pem files he created. So far so good..

Now, he's using openssl rsautl to encrypt and decrypt strings for our group.
So far so good..

He's calling openssl rsautl from a c# script to encrypt and decrypt these
strings. So far so good..

Now here is what I want to do. I want to use c#'s built in rsa class to
encrypt and decrypt these strings instead of having the c# script call
openssl rsautl. So far so good..

On this link below there is an example of c# calling and ecrypting with a
public key, you don't have to go to this link..just for reference.
http://msdn.microsoft.com/en-us/library/system.security.cryptography.rsacryptoserviceprovider.encrypt.aspx

Now in this script before the encrypt function is called there are two lines
of code:

byte[] Exponent = {1,0,1};

RSAKeyInfo.Exponent = Exponent;


If I try to remove this it throws an error. So I am guessing that a
exponent needs to

be defined in order to encrypt a message????Yes, no, I'm missing something..


In your response to my first email, you said e and n are needed for
encrypting. If there is no e being passed in as an argument to openssl
rsautl, what is the default e? and what is the default n?




On Sun, May 23, 2010 at 6:11 PM, Dave Thompson <dthomp...@prinpay.com>wrote:

> >       From: owner-openssl-us...@openssl.org On Behalf Of Pareto, Charles
> >       Sent: Friday, 21 May, 2010 17:14
>
> >       I'm trying to get the same result with the c#
> RSACryptoServiceProvider class
> > that 'openssl.exe rsautl ' gives me.
> >
> >       The c# class wants more properties set before you can encrypt a
> message.
>
> I can't help with C#, but this borders on an abstract crypto issue.
>
> >       How can I obtain the parameters that 'openssl.exe rsautl'
> implements.
> > For example the exponent, q parameters, p parameters, dp, dq parameters,
> etc.
> > These are optional arguments for the c# class.
> >       Ex. Exponent = {1,0,1}
>
> d,p,q,dP,dQ,qInv are the components of an RSA private key that are not
> in the public key. And except for the first, only in the CRT (Chinese
> Remainder Theorem) form, which is used widely including by openssl.
> If that 'exponent' is notated in bytes, it would be 65537 aka 'F4',
> a commonly used value for the public exponent e. The private exponent
> d must be much larger, and for usual e will appear random.
>
> >       > openssl.exe rsautl -encrypt -inkey dir\\public.pem -pubin -in
> filename -out encryptedfilename
>
> Aside: unless you're using a Unixoid shell glomped onto Windows,
> like mingw, you usually don't need to specify .exe to find an
> executable and don't need to double backslashes in pathnames.
>
> RSA encrypt, or verify, uses and should need only the public key,
> which substantively consists only of e and n (where n = p * q).
> The private key fields are needed, and generally should be used,
> only for decrypt, or sign. That's the way public-key crypto works,
> and provides certain (we hope useful!) security features.
> You can see public.pem does not contain and this command can't use
> private bits with openssl rsa -in public.pem -pubin -noout -text
> (Note however that rsautl -decrypt does need the private key.)
>
> If some part of C# really demands a private key to RSA *encrypt*,
> it is hopelessly broken and could never provide useful security.
> Although M$ certainly makes mistakes from time to time, I would
> be very surprised if they made such a basic and obvious one, so
> I suspect your understanding is actually wrong. Perhaps you aren't
> (correctly) doing something needed to tell it to be in encrypt mode,
> or (more abstractly) to use a public rather than private RSA key.
>
>
>
>
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