2009/6/6 Michael S. Zick <open...@morethan.org>:
> On Sat June 6 2009, jaze lee wrote:
>>
>> i  still not understand the problem. although i don''t get the result.
>>
>
> Q1: Why is this problem "hard" - as in: "computationally hard" ?
>
> A1: There are two many number trials (computations) required in a
> "cryptographically hard" number.
>
> True, for any brute force approach.
>
> My apologies in advance to any and all mathematicians reading this... ;)
>
> Q2: But is it all that hard for something other than "brute force"?
> Q3: Where did that "approximately 300 decimal digits" come from?
>
> Actually, 10^316 is the better approximation of "cryptographically hard"
> as will be seen shortly.
>
> Hyp1: We want to give up on any "try each number computationally" (brute 
> force).
>
> Q4: If we don't try all numbers (in a range), how do we know when (if)
> we have found all of the prime numbers in that range?
>
> We can throw out the obvious and those that violate the definition of prime.
> Numbers divisible by 1 don't matter - that divisor is allowed by definition.
> Like, all even numbers (they are divisible by 2) -
>
> DAQ1: How many integer numbers are there?  (an uncountable value)
> DAQ2: How many after we throw away all the even ones?  (an uncountable value)
>
> Obviously, this isn't leading to a simplification of the problem; re-think...
> List the first few prime numbers, just so they are in front of us:
> 1, 2, 3, 5, 7, 11, 13 ... to (an uncountable value - see: DAQ1 & DAQ2)
>
> Q5: Is there some way to know how many prime numbers there are, less than x?
> Ans: Yes, several of them - within limitations.
> We know from above that there must be at least one prime number between
> 13 (the largest we know of) and twice that number (26).
>
> If we know that it is not practical to test each number, then whatever means
> we use, we have to know when to stop trying (because we found them all).
>
> Enter here, the: "Prime Number Theorem" (google it).
> and the "prime counting function" [I'll write: pc(x)].
> The first approximation found for pc(x) was: x div (Ln(x)
> Carl Gauss found a 'better' approximation for pc(x) was: Li(x)
>
> So now our problem is: find all primes between 13..26, stop when we have
> found: pc(26) - pc(13) new primes.
> Use whatever search and trial method you like - with modern 32bit and 64bit
> integer machines common, you can have a lot of fun finding primes and learning
> ways to search for them.  You know you could try a modified, binary search 
> for one.
>
> Q6: But will this approach always work?
> A6: No.  (I almost had you, didn't I?)
> Google: "Skewes' number"
>
> That is the smallest, natural, number for which: pc(x) is approximately: 
> Li(x) is false.
> In fact, pc(x) > Li(x) is true (by definition of a Skewes Number).
>
> So if we can't pre-determine how many prime numbers there is in the range we 
> are
> considering, how do we know when to stop looking?
>
> Modern, computerized, studies place the smallest number for which pc(x) > 
> Li(x)
> is true at about 1.397*10^316.
>
> A1..5: One workable (layman's) definition of "cryptographically hard" 
> (10^316).
>
> I.E: Any method you come up with for your prime-finding will fail, since you
> don't know how many primes there are in that range, you don't know when to
> stop "prime-finding", hence you have to test them all (brute force, again).
> And we are already agreed that brute force is not practical.
>
> Hope this helps (and that true mathematicians don't black-ball me from the 
> ml).
 That is , n = q*p , we can choose the prime has given bits, but we
can not know all that prime in that range.if
we want to know the range , we should test it every odd number in that
range, or should  find a function that can do the job efficiently .
The problem is we can not find the function yet ? or some other ways
to judge a big integer whether it's a prime. Is it so-called
mathematics problem that many cipher based on it ?

>
> Mike
>
>
>
>
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