You must save original pointer because i2c and i2d function move pointer in order to prepare it for subsequent calls.
ASN1_INTEGER * serial; unsigned char * serialNumberDER,*temp; size = i2c_ASN1_INTEGER(serial, NULL); temp=serialNumberDER = new unsigned char[*size]; size = i2c_ASN1_INTEGER(serial, &temp); serialNumberDER contains required value francesco petruzzi ----- Original Message ----- From: "Andrzej Posiadala" <[EMAIL PROTECTED]> To: <[EMAIL PROTECTED]> Sent: Wednesday, February 11, 2004 1:57 PM Subject: How to convert internal ASN1_INTEGER into little endian content octets > Hi , > > i'm trying to convert ASN1_INTEGER (specifically certificate serial > number) into its DER representation. > I'm using i2c_ASN1_INTEGER - and if it's the right function - then I don't > understand why it moves a pointer passed to it as second parameter behind > reserved memory. > Here is what I'm doing: > > int size; > ASN1_INTEGER * serial; > unsigned char * serialNumberDER; > > size = i2c_ASN1_INTEGER(serial, NULL); > serialNumberDER = new unsigned char[*size]; > size = i2c_ASN1_INTEGER(serial, & serialNumberDER); > > The function has this code at the end: > > *pp+=ret; > > where pp is a pointer to serialNumberDER, so in effect it moves > serialNumberDER behind created array of unsigned char. > > Please, explain it to me. > Thanks in advance. > > ______________________________________________________________________ > OpenSSL Project http://www.openssl.org > User Support Mailing List [EMAIL PROTECTED] > Automated List Manager [EMAIL PROTECTED] ______________________________________________________________________ OpenSSL Project http://www.openssl.org User Support Mailing List [EMAIL PROTECTED] Automated List Manager [EMAIL PROTECTED]
