As far as I know, it does pad one more block on already complete boundaries. So it is behaving as expected. Muni -----Original Message----- From: Shobhit Kanaujia [mailto:[EMAIL PROTECTED]] Sent: Wednesday, August 08, 2001 2:20 PM To: '[EMAIL PROTECTED]' Subject: DES Hello everyone, I am using the command openssl enc -des ........... for encryption. I am wondering whether there is any flaw in openssl or in my thinking, because I gave it exactly 128 bits to encrypt and it gives me 128+64 bits as the result. I thought that 128 bits should give me 128 bits of encrypted text. I was thinking that openssl would pad the input so that it ends on a 64 bit boundary, and so it should not pad the 128 bit input. But it seems that it does pad it with 64 bits. Does anyone know anything about this? Any suggestions/tips are welcome. Thanks, _Shobhit! ______________________________________________________________________ OpenSSL Project http://www.openssl.org User Support Mailing List [EMAIL PROTECTED] Automated List Manager [EMAIL PROTECTED] ______________________________________________________________________ OpenSSL Project http://www.openssl.org User Support Mailing List [EMAIL PROTECTED] Automated List Manager [EMAIL PROTECTED]
