I should have said uint8_t * to uint32_t *. The problem is that that
there is a lot of distance between where the conversion to uint8_t *
happens and where the cast back to uint32_t * happens.
It is not obvious at all from the context that there is an alignment
guarantee.
Hence the simplest solution is to write a fn(the one that I wrote is
correct), to handle unaligned uint32_t access.
The version below yields decent code across architectures after
Stefan showed that the mileage varies greatly with intrinsic memcpy().
#include <string.h>
#include <stdint.h>
uint32_t uint32_read_unaligned(const uint8_t *data)
{
uint32_t t;
// Let's trust the compiler to do something very clever here.
int i;
for (i = 0; i < sizeof(t); i++)
{
((uint8_t *)&t)[i] = data[i];
}
return t;
}
--
Øyvind Harboe - Can Zylin Consulting help on your project?
US toll free 1-866-980-3434 / International +47 51 87 40 27
http://www.zylin.com/
_______________________________________________
Openocd-development mailing list
Openocd-development@lists.berlios.de
https://lists.berlios.de/mailman/listinfo/openocd-development
