Perhaps I should have left a clearer note. The bug is still there, no one worked on it yet.
Changing to the default constructor at least works as expected - the large white square (selected color) appears over the right spot. In the original example, the Color.CORAL is apparently not a part of the palette, so instead the white (incorrect) square appears at the wrong place. Change the constructor argument to a color which is present in the palette and it would work as expected. This is just a workaround, the bug is still there. -andy From: openjfx-dev <openjfx-dev-r...@openjdk.org> on behalf of PavelTurk <pavelturk2...@gmail.com> Date: Thursday, May 9, 2024 at 07:56 To: openjfx-dev@openjdk.org <openjfx-dev@openjdk.org> Subject: There is no workaround for JDK-8324327 Hello all. This is about https://bugs.openjdk.org/browse/JDK-8324327 . Andy Goryachev wrote in comment "Change to the default constructor and the issue disappears". I don't see that using default constructor solves the problem. I tried the following code : public class JavaFxTest7 extends Application { public static void main(String[] args) { launch(args); } @Override public void start(Stage primaryStage) { VBox root = new VBox(); ColorPicker picker = new ColorPicker(); root.getChildren().addAll(picker); var scene = new Scene(root, 400, 300); primaryStage.setScene(scene); primaryStage.show(); } } and I have the same bug. JavaFX: 23-ea+3 Java: 21.0.2 OS: Ubuntu 20.04.3 LTS So, ColorPicker is always broken. Best regards, Pavel
