On Wed, 27 Mar 2024 18:30:24 GMT, Andy Goryachev <ango...@openjdk.org> wrote:
> the end result of stepping once by `amountToStepBy` must be equivalent of > incrementing by one a total of `amountToStepBy` times, wouldn't you agree? Yes, this is the expectaion. > so the formula for positive `amountToStepBy` values should look like > > `((val + amountToStepBy) % (max - min)) + min` > > or something along these lines. Not quite. Because the range is inclusive on both ends, the number of discrete positions is `max - min + 1`. In your above example , where `min=0` and `max=100`, there are 101 discrete positions. A single step by 101 or 101 steps by 1 will both bring you back to the same position you started from. ------------- PR Comment: https://git.openjdk.org/jfx/pull/1431#issuecomment-2023752621
