From: Ross Burton <r...@burtonini.com>
If the function a ThreadedWorker is executing raises an exception, don't
use print() as that mostly disappears. Instead, output it to the logger.
This is done using bb.mainlogger.debug directly instead of bb.debug() as
this allows us to pass the exception instance directly, which is then
incorporated into the log stream.
Signed-off-by: Ross Burton <ross.bur...@arm.com>
Signed-off-by: Richard Purdie <richard.pur...@linuxfoundation.org>
(cherry picked from commit 2f1ea25c222b344dd8b784b2bc73a6540ab30274)
Signed-off-by: Steve Sakoman <st...@sakoman.com>
---
meta/lib/oe/utils.py | 3 ++-
1 file changed, 2 insertions(+), 1 deletion(-)
diff --git a/meta/lib/oe/utils.py b/meta/lib/oe/utils.py
index 83d298906b..3e016244c5 100644
--- a/meta/lib/oe/utils.py
+++ b/meta/lib/oe/utils.py
@@ -481,7 +481,8 @@ class ThreadedWorker(Thread):
try:
func(self, *args, **kargs)
except Exception as e:
- print(e)
+ # Eat all exceptions
+ bb.mainlogger.debug("Worker task raised %s" % e, exc_info=e)
finally:
self.tasks.task_done()
--
2.25.1
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