Sorry for not being very clear. You're correct, pst_file is a struct with
d_head being a pointer to another struct. Within libpst (the C library I'm
working with), when you call pst_open() you pass pst_file by reference
which opens the PST file (MS outlook file) and populates the pst_file
struct. d_head is a pointer to another struct that holds individual
records pulled out of the PST file. When the pst_open() call returns I
need to take the d_head pointer, assign it to another pointer variable of
type pst_desc_tree and use that to pass into another function.
pst_item *item = NULL;
pst_desc_tree *d_ptr;
pst_open(&pstfile, file_name, NULL);
d_ptr = pstfile.d_head; // first record is main record
item = pst_parse_item(&pstfile, d_ptr, NULL);
The way I did it which seems to work is:
var f = new pst_file(); //the main pst_file struct
var pstdesctree_Ptr = ref.refType(pst_desc_tree);
var d_ptr = ref.alloc(pstdesctree_Ptr);
ref.writePointer(d_ptr, 0, f.d_head);
This seems to copy the correct pointer, however when I do:
ref.deref(d_ptr)
I get a segmentation fault.
How would I get access to the variables stored in that struct inside node?
Here is my code: https://github.com/rhasson/node-libpst
I didn't finish converting all the structs yet but give you an idea of what
the code looks like. In the SRC directory I included the .c and .h files
so you can see the structures.
Thanks,
Roy
On Thursday, August 23, 2012 1:15:15 PM UTC-4, Nathan Rajlich wrote:
>
> > In C I do this:
> > typedef struct pst_file {
> > pst_desc_tree *d_head
> > } pst_file;
> >
> > pst_desc_tree *d_ptr; //this is another struct
> > d_ptr = pstfile.d_head;
>
> It's a pointer to a struct actually. I think you need to explain more
> what you intend to do with the variable after. Are you trying to make
> a duplicate of the struct? It seems to me that what you have above
> would be achieved with "pstfile.d_head.slice(0)" but I can't really
> imagine what you would need that for.
>
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