One of the more common cases of allocation size calculations is finding
the size of a structure that has a zero-sized array at the end, along
with memory for some number of elements for that array. For example:

struct foo {
    int stuff;
    struct boo entry[];
};

size = sizeof(struct foo) + count * sizeof(struct boo);
instance = alloc(size, GFP_KERNEL)

Instead of leaving these open-coded and prone to type mistakes, we can
now use the new struct_size() helper:

size = struct_size(instance, entry, count);
instance = alloc(size, GFP_KERNEL)

This code was detected with the help of Coccinelle.

Signed-off-by: Gustavo A. R. Silva <gust...@embeddedor.com>
---
 net/sched/act_pedit.c | 2 +-
 1 file changed, 1 insertion(+), 1 deletion(-)

diff --git a/net/sched/act_pedit.c b/net/sched/act_pedit.c
index 2b372a06b432..3663d3b615a4 100644
--- a/net/sched/act_pedit.c
+++ b/net/sched/act_pedit.c
@@ -406,7 +406,7 @@ static int tcf_pedit_dump(struct sk_buff *skb, struct 
tc_action *a,
        struct tcf_t t;
        int s;
 
-       s = sizeof(*opt) + p->tcfp_nkeys * sizeof(struct tc_pedit_key);
+       s = struct_size(opt, keys, p->tcfp_nkeys);
 
        /* netlink spinlocks held above us - must use ATOMIC */
        opt = kzalloc(s, GFP_ATOMIC);
-- 
2.20.1

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