One of the more common cases of allocation size calculations is finding the size of a structure that has a zero-sized array at the end, along with memory for some number of elements for that array. For example:
struct foo { int stuff; struct boo entry[]; }; instance = kvzalloc(sizeof(struct foo) + count * sizeof(struct boo), GFP_KERNEL); Instead of leaving these open-coded and prone to type mistakes, we can now use the new struct_size() helper: instance = kvzalloc(struct_size(instance, entry, count), GFP_KERNEL); This code was detected with the help of Coccinelle. Signed-off-by: Gustavo A. R. Silva <gust...@embeddedor.com> --- drivers/net/ethernet/chelsio/cxgb4/clip_tbl.c | 3 +-- 1 file changed, 1 insertion(+), 2 deletions(-) diff --git a/drivers/net/ethernet/chelsio/cxgb4/clip_tbl.c b/drivers/net/ethernet/chelsio/cxgb4/clip_tbl.c index 5701272aa7f7..ce28820c57c9 100644 --- a/drivers/net/ethernet/chelsio/cxgb4/clip_tbl.c +++ b/drivers/net/ethernet/chelsio/cxgb4/clip_tbl.c @@ -289,8 +289,7 @@ struct clip_tbl *t4_init_clip_tbl(unsigned int clipt_start, if (clipt_size < CLIPT_MIN_HASH_BUCKETS) return NULL; - ctbl = kvzalloc(sizeof(*ctbl) + - clipt_size*sizeof(struct list_head), GFP_KERNEL); + ctbl = kvzalloc(struct_size(ctbl, hash_list, clipt_size), GFP_KERNEL); if (!ctbl) return NULL; -- 2.20.1