On Sun, Dec 16, 2018 at 8:32 AM Vlad Buslov <vla...@mellanox.com> wrote:
>
> On Thu 13 Dec 2018 at 23:32, Cong Wang <xiyou.wangc...@gmail.com> wrote:
> > On Tue, Dec 11, 2018 at 2:19 AM Vlad Buslov <vla...@mellanox.com> wrote:
> >>
> >> As a part of the effort to remove dependency on rtnl lock, cls API is being
> >> converted to use fine-grained locking mechanisms instead of global rtnl
> >> lock. However, chain_head_change callback for ingress Qdisc is a sleeping
> >> function and cannot be executed while holding a spinlock.
> >
> >
> > Why does it have to be a spinlock not a mutex?
> >
> > I've read your cover letter and this changelog, I don't find any
> > answer.
>
> My initial implementation used mutex. However, it was changed to
> spinlock by Jiri's request during internal review.
>

So what's the answer to my question? :)


> >
> >>
> >> Extend cls API with new workqueue intended to be used for tcf_proto
> >> lifetime management. Modify tcf_proto_destroy() to deallocate proto
> >> asynchronously on workqueue in order to ensure that all chain_head_change
> >> callbacks involving the proto complete before it is freed. Convert
> >> mini_qdisc_pair_swap(), that is used as a chain_head_change callback for
> >> ingress and clsact Qdiscs, to use a workqueue. Move Qdisc deallocation to
> >> tc_proto_wq ordered workqueue that is used to destroy tcf proto instances.
> >> This is necessary to ensure that Qdisc is destroyed after all instances of
> >> chain/proto that it contains in order to prevent use-after-free error in
> >> tc_chain_notify_delete().
> >
> >
> > Please avoid async unless you have to, there are almost always bugs
> > when playing with deferred workqueue or any other callbacks.
>
> Indeed, async Qdisc and tp deallocation introduces additional
> complexity. What approach would you recommend to make chain_head_change
> callback atomic?

I don't look into any of your code yet, from my understanding of your
changelog, it seems all these workqueue stuffs can be gone if you can
make it a mutex instead of a spinlock.

This is why I stopped here and wait for your answer to my above question.

Thanks.

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