On Mon, Nov 13, 2006 at 11:22:00PM +0300, Alexey Dobriyan wrote:
> 6.5.7(5): The result of E1 >> E2 is E1 right-shifted E2 bit positions.
>               ...
>       If E1 has a signed type and a negative value, the resulting value
>       is implementation defined.
> 
> So, cast -1 to unsigned type to make result well-defined.

Or just use ~0U and be done with that.
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