On 4/23/18 5:25 AM, Edward Cree wrote:
On 20/04/18 23:18, Yonghong Song wrote:
diff --git a/kernel/bpf/verifier.c b/kernel/bpf/verifier.c
index 3c8bb92..01c215d 100644
--- a/kernel/bpf/verifier.c
+++ b/kernel/bpf/verifier.c
@@ -2975,6 +2975,32 @@ static int adjust_scalar_min_max_vals(struct 
bpf_verifier_env *env,
                /* We may learn something more from the var_off */
                __update_reg_bounds(dst_reg);
                break;
+       case BPF_ARSH:
+               if (umax_val >= insn_bitness) {
+                       /* Shifts greater than 31 or 63 are undefined.
+                        * This includes shifts by a negative number.
+                        */
+                       mark_reg_unknown(env, regs, insn->dst_reg);
+                       break;
+               }
+               if (dst_reg->smin_value < 0)
+                       dst_reg->smin_value >>= umin_val;
+               else
+                       dst_reg->smin_value >>= umax_val;
+               if (dst_reg->smax_value < 0)
+                       dst_reg->smax_value >>= umax_val;
+               else
+                       dst_reg->smax_value >>= umin_val;
+               if (src_known)
+                       dst_reg->var_off = tnum_rshift(dst_reg->var_off,
+                                                      umin_val);
tnum_rshift is an unsigned shift, it won't do what you want here.
I think you could write a tnum_arshift that looks something like this
  (UNTESTED!):

     struct tnum tnum_arshift(struct tnum a, u8 shift)
     {
         return TNUM(((s64)a.value) >> shift, ((s64)a.mask) >> shift);
     }
Theory: if value sign bit is 1 then number is known negative so populate
  upper bits with known 1s.  If mask sign bit is 1 then number might be
  negative so populate upper bits with unknown.  Otherwise, number is
  known positive so populate upper bits with known 0s.

Right, my last version just used this tnum_arshift :-).


+               else
+                       dst_reg->var_off = tnum_rshift(tnum_unknown, umin_val);
Applying the above here, tnum_arshift(tnum_unknown, ...) would always just
  return tnum_unknown, so just do "dst_reg->var_off = tnum_unknown;".
The reason for the corresponding logic in the BPF_RSH case is that a right
  logical shift _always_ populates upper bits with zeroes.
In any case these 'else' branches are currently never taken because they
  fall foul of the check Alexei added just before the switch,
     if (!src_known &&
         opcode != BPF_ADD && opcode != BPF_SUB && opcode != BPF_AND) {
         __mark_reg_unknown(dst_reg);
         return 0;
     }
So I can guarantee you haven't tested this code :-)

I just noticed this last night and removed the !src_known branch all together here and from LSH/RSH.


+               dst_reg->umin_value >>= umax_val;
+               dst_reg->umax_value >>= umin_val;
FWIW I think the way to handle umin/umax here is to blow them away and
  just rely on inferring new ubounds from the sbounds (i.e. the inverse of
  what we do just above in case BPF_RSH) since BPF_ARSH is essentially an
  operation on the signed value.  I don't think there is a need to support
  cases where the unsigned bounds of a signed shift of a value that may
  cross the sign boundary at (1<<63) are needed to verify a program.
(Unlike in the unsigned shift case, it is at least _possible_ for there to
  be information from the ubounds that we can't get from the sbounds - but
  it's a contrived case that isn't likely to be useful in real programs.)

This makes sense and will make code simpler and easy to understand.
Will make the change.

Thanks!


-Ed
+               /* We may learn something more from the var_off */
+               __update_reg_bounds(dst_reg);
+               break;
        default:
                mark_reg_unknown(env, regs, insn->dst_reg);
                break;

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