On Wed, Feb 7, 2018 at 11:38 PM, Jiri Pirko <j...@resnulli.us> wrote: > Thu, Feb 08, 2018 at 12:08:36AM CET, xiyou.wangc...@gmail.com wrote: >>On Tue, Feb 6, 2018 at 11:01 PM, Jiri Pirko <j...@resnulli.us> wrote: >>> Wed, Feb 07, 2018 at 06:09:15AM CET, xiyou.wangc...@gmail.com wrote: >>>>Hi, Jiri >>>> >>>>Your commit 7fa9d974f3c2a016b9accb18f4ee2ed2a738585c >>>>breaks the tc script by Paweł. Please find below for details. >>> >>> Did you do the bisection? >>> The commit just uses block struct instead of q, but since they >>> are in 1:1 relation, that should be equvivalent. So basically you still >>> have per-qdisc hashtables for u32. >> >>Well, at least the following fixes the problem here. But I am not sure >>if it is expected too for shared block among multiple qdiscs. > > For shared block, block->q is null.
According to this comment: /* block_index not 0 means the shared block is requested */ and the code, if (!block) { block = tcf_block_create(net, q, extack); block->q is set to q, and q is always non-NULL AFAIU. Also, I don't know if it is intended, but block->q always points to the parent qdisc rather than the qdisc attached to a class. >> >> >>@@ -338,7 +330,7 @@ static struct hlist_head *tc_u_common_hash; >> >> static unsigned int tc_u_hash(const struct tcf_proto *tp) >> { >>- return hash_ptr(tp->chain->block, U32_HASH_SHIFT); >>+ return hash_ptr(tp->chain->block->q, U32_HASH_SHIFT); >> } >> >> static struct tc_u_common *tc_u_common_find(const struct tcf_proto *tp) >>@@ -348,7 +340,7 @@ static struct tc_u_common *tc_u_common_find(const >>struct tcf_proto *tp) >> >> h = tc_u_hash(tp); >> hlist_for_each_entry(tc, &tc_u_common_hash[h], hnode) { >>- if (tc->block == tp->chain->block) >>+ if (tc->block->q == tp->chain->block->q) > > :O I don't get it. tc->block is pointer, tc->block->q is pointer. And > they are different at the same time for non-shared block. If you look into Pawel's script, a new block is created for each class therefore a different tc_u_common is created which causes the ht 9:22 can't be found.