Yes indeed, but you don't have to justify much if you only ask for the minimum, if you want more you need to ask...
Also, and this I like less, your membership is calculated from the number of IPs you have... I think in short $$=max(1180x1.3(log2(Addresses in /32)-8),Feev6 = 1180x1.3(log2(Addresses in /56)-22) http://www.apnic.net/services/apply-for-resources/check-your-eligibility/check-ipv6 http://www.apnic.net/services/become-a-member/how-much-does-it-cost ----- Original Message ----- From: "Randy Carpenter" <rcar...@network1.net> To: "Franck Martin" <fra...@genius.com> Cc: nanog@nanog.org, "Nick Hilliard" <n...@foobar.org> Sent: Wednesday, 27 October, 2010 10:48:13 AM Subject: Re: IPv6 Routing table will be bloated? It would be nice as a start, but does not really take into consideration future expansion needs. I would think that you could draw some parallels, though. Something like: v4 /16 ~ v6 /32 v4 /12 ~ v6 /28 v4 /8 ~ v6 /24 I know it we don't want to equate v4 and v6, but it may help as a guideline for the size of the customer base.
