Normally, I don't participate in this sort of thing, but I'm a sucker
for a "there's more than one way to do it" challenge.
Shadow wrote:
Robert D. Scott wrote:
The harder way:
Decimal: 1089055123
Hex (dashes inserted at octals): 40-E9-A9-93
Decimal (of each octet): 64-233-169-147
IP Address: 64.233.169.147
The "this could take all day" way :
(in bc with scale=0 for integer portions only)
1089055123/(2^24)%(2^8)
64
1089055123/(2^16)%(2^8)
233
1089055123/(2^8)%(2^8)
169
1089055123/(2^0)%(2^8)
147
(Note: 2^0=1 & x/1=x so last line could reduce to 1089055123%(2^8).)
-Nicholas
[EMAIL PROTECTED]
The "ugly, please adjust according to your endianness, etc" way:
int *dec;
unsigned char *oct1, *oct2, *oct3, *oct4;
main(int argc, char **argv) {
dec = malloc(sizeof(int));
*dec = 1089055123;
oct4 = dec;
oct3 = oct4 + sizeof(char);
oct2 = oct3 + sizeof(char);
oct1 = oct2 + sizeof(char);
printf("dec: %lu ip: %hu.%hu.%hu.%hu\n", *dec, *oct1, *oct2, *oct3,
*oct4);
}
