SELECT n.uid, n.name from names_tables n LEFT OUTER JOIN exclude
ON n.uid = exclude.n_uid WHERE exclude.n_uid IS NULL

> -----Original Message-----
> From: Michelle de Beer [mailto:[EMAIL PROTECTED]] 
> Sent: Wednesday, December 11, 2002 3:22 PM
> To: mysql list
> Subject: Select Where !=
> 
> 
> I have two tables. One with names and one for
> excluding certain names. Exclude-table contains the
> uid for the name excluded.
> 
> If I want to see which names has been excluded, this
> query does the job:
> Select n.uid, n.name from names_tables n, exclude
> WHERE n.uid = exclude.n_uid 
> 
> But if I want to select all names, but leave out the
> ones that are in the "exclude"-table, I thought this
> would do it, but no.
> Select n.uid, n.name from names_tables n, exclude
> WHERE n.uid != exclude.n_uid 
> 
> It has something to do with the != thingy...
> 
> Any thoughts?
> // Michelle
> sql, query
> 
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