your variable is not the result of mysql_query() empty, contains something else or whatever
Am 21.09.2011 14:16, schrieb valery-christian: > the meaning of Warning: mysql_fetch_array(): supplied argument is not a valid > MySQL result resource in C:\Program Files\EasyPHP 2.0b1\www\memo3\index.php > on line 64 > -- Mit besten Grüßen, Reindl Harald the lounge interactive design GmbH A-1060 Vienna, Hofmühlgasse 17 CTO / software-development / cms-solutions p: +43 (1) 595 3999 33, m: +43 (676) 40 221 40 icq: 154546673, http://www.thelounge.net/ http://www.thelounge.net/signature.asc.what.htm
signature.asc
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