How about this?
SELECT
`first_table`.`names`
, `first_table`.`version`
, (SELECT
COUNT(`other_table`.`names`)
FROM `other_table`
WHERE `other_table`.`this_id` = `first_table`.`id`) AS 'count'
FROM `first_table`
WHERE `first_table`.`progress` > 0;
Granted, you have not provided structure or names of the tables so this is
just my interpretation, but maybe something like this could give you a
starting point?
Steven Staples
> -----Original Message-----
> From: Michael Stroh [mailto:[email protected]]
> Sent: June 3, 2010 11:24 AM
> To: MySql
> Subject: Help needed on query on multiple tables
>
> Hi everyone. I'm trying to create a certain MySQL query but I'm not sure
> how to do it. Here is a stripped down version of the result I'm aiming
for.
> I'm pretty new to queries that act on multiple tables, so apologize if
this
> is a very stupid question.
>
> I have one table (data) that has two columns (names and progress). I have
a
> second table (items) that has two columns (names and version). I'd like to
> do a query that produces the name of every record in data that has
progress
> set to 0 and the number of records in the items table that have the same
> value in each table.names field.
>
> I can perform this by using two sets of queries, one that queries the data
> table and then loop through the names to do a count(names) query, but I'm
> not sure if I can somehow do it in one query.
>
> Thanks in advance!
> Michael
>
>
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