Instead of:
-> else 2003
-> where id between 1 and 6;
Try
-> else 2003
-> end
-> where id between 1 and 6;
Or maybe even:
mysql> update table1
-> set year=case when id IN (1, 2, 4) then 2000
-> when id IN(2, 4, 6) then 2001
-> else 2003
-> end
-> where id between 1 and 6;
Good luck!
Regards,
m
-----Original Message-----
From: MuraliKrishna [mailto:murali_kris...@arthaoptions.com]
Sent: Friday, February 05, 2010 12:04 PM
To: mysql@lists.mysql.com
Subject: help me out for this problem...
Here I have to update year column with reference to the row id
mysql> update table1
-> set year=case when id=1 then 2000
-> when id=2 then 2001
-> when id=3 then 2000
-> when id=4 then 2001
-> when id=5 then 2000
-> when id=6 then 2001
-> else 2003
-> where id between 1 and 6;
ERROR 1064 (42000): You have an error in your SQL syntax; check the manual
that
corresponds to your MySQL server version for the right syntax to use near
'where
id between 1 and 6' at line 9
mysql>
----------------------------------------------------------------------
Urocze domki...
Zobacz >>> http://link.interia.pl/f25aa
--
MySQL General Mailing List
For list archives: http://lists.mysql.com/mysql
To unsubscribe: http://lists.mysql.com/mysql?unsub=arch...@jab.org
