Yes, you are right. It's the json_encode that fail.
It's strange though. The data that fail is "Humlebæk".
Another query, in another form, returning "Værksted" don't
fail in json_encode.
echo $cust['oname']; give the correct value.
On Tue, September 22, 2009 22:56, Mark Goodge wrote:
> Mogens Melander wrote:
>> Well, no typos.
>>
>> The relevant piece of code:
>>
>> if (! $cust = mysql_fetch_assoc($res))
>> {
>> echo "{success: false, errors: { reason: 'Fetch Customer failed: " .
>> htmlspecialchars(mysql_error(),ENT_QUOTES) .
>> "<br>" . htmlspecialchars($sql,ENT_QUOTES) . "'}}";
>> }
>> else
>> {
>> echo "{success: true, total: 1, results:[" . json_encode($cust) . "]}";
>> }
>>
>
> What happens if you simplify the PHP?
>
>
> $cust = mysql_fetch_assoc($res);
> print_r($cust);
>
>
> That will tell you what PHP is seeing from MySQL. If the results have
> the correct values, then the problem is elsewhere in the code.
>
> I suspect that the problem is in the json_encode() function. According
> to the PHP documentation this requires utf8-encoded data. If your values
> in oname are not utf8, then that may explain why the function is
> returning a 'null' where it should have a string.
>
> Mark
>
>
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Later
Mogens Melander
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