In order to make your workaround less tedious you can write a shell script
that dumps the structures of all 50 databases
basically:
for db in $(mysql [opts] -e 'show databases'); do
mysqldump [opts] $db
Done
Olaf
On 10/5/08 10:15 PM, "Uma Bhat" <[EMAIL PROTECTED]> wrote:
> Hey guys!
>
> We are in progress of *optimizing* and designing the existing mysql database
> enviromnent on *linux*. And need help in comaparing schema of 50
> databases from the same mysql instance.
>
> *MySQL version 5.0*
>
> *SCENARIO* - There are 50 mysql databases (which we have been informed that
> is of same schema - we are not sure)
> We are planning to consolidate the data spread across these 50 databases
> into a SINGLE database . Hence before doing this, *we want to ensure that
> there is ABSOLUTE *no* difference in schema between each of them. (all
> datatypes, and other such database objects, engines, MUST be IDENTICAL).*
>
> *QUESTION* - what's the *EASIET way to compare* the schema's of ALL these 50
> databases ?
>
> *WORKAROUND* i could think of - taking *mysqldump* of database (with *
> --no-data* option) and compare with *'diff'* UNIX command.
>
> BUT, this is a VERY TEDIOUS to carry out this process for 50 databases!!!
>
>
> *Are there any tools available* to accomplish this task?
>
>
> Many Thanks!
> Uma
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