I have a question about the subshell that is started up when you use the ! command. The manual says: shell-escape (default: !) Asks for an external Unix command and executes it. The ``$wait_key'' can be used to control whether Mutt will wait for a key to be pressed when the command returns (presumably to let the user read the output of the command), based on the return status of the named command. This doesn't really tell us what the subshell is. What I get when I press ! is: Shell command: but if I enter any function (eg, jay) I've defined in my .bashrc or .bash_login (bash is my shell), I get sh: jay: command not found Press any key to continue... Apparently the subshell is sh. I have to press enter and then I get the prompt bash$ (I have the command, set shell="/usr/bin/bash" in the second line of .muttrc). I can then type in my command and then exit the bash subshell. So, my question is how can I avoid this sh subshell and get a bash subshell instead straight off. I don't want to have to press enter and then type exit after. -- Greg Matheson Chinmin College, Taiwan [EMAIL PROTECTED]
