Exactly. Note that this will fail on python3 though, because "unicode"
doesn't exist.
On Mon, Feb 11, 2013 at 9:32 PM, Alexander Bolotnov <abolot...@gmail.com> wrote:
> got you, so the following in publish():
>
> if isinstance(payload, str) == True or isinstance(payload, bytearray) ==
> True:
> local_payload = payload
>
> should actually be something like
>
> if payload and type(payload) in (str, unicode, bytearray):
> local_payload = payload
>
> I guess
> thanks,
>
>
>
> Sasha Bolotnov
> www.bolotnov.info
>
>
>
> On Tue, Feb 12, 2013 at 1:20 AM, Roger Light <ro...@atchoo.org> wrote:
>>
>> Hi
>>
>> > I'm now using a dirty walkaround:
>> >
>> > def send_message(self, topic, message):
>> > if type(message) == unicode:
>> > message = str(message).encode('string_escape')
>> > result, some_number = Client.mc.publish(topic, message)
>>
>> mosquitto.py does actually support python 2.7 unicode data types later
>> down the line, it just rejects them at the publish() call by mistake.
>> For both python 2.7 and python 3, the _send_publish() function calls
>> message.encode('utf-8') to encode as utf-8. If you want to use a
>> different encoding just call message.encode('.....') before passing it
>> to the publish() call.
>>
>> Cheers,
>>
>> Roger
>
>
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