The file size is a thing, the used memory is another thing.
Doesn't matter that a 2048x2048 24bit image can be saved as jpg in
100kb file or in a 10kb file, the things that matter is the memory
used per pixel that, means, tipically for a jpg, 3/4 bytes per pixel.
So if you have a 2048x2048 image that needs 3 bytes per pixel you will
need, at least 12582912 bytes (12mb) in memory, if 4 bytes per pixel
you will need at least 16777216 bytes (16mb).
As i said, it will need at least that memory because you should
consider the memory used for 4 bytes alignment (stride) that is per
row that may grow up used memory.
2012/6/18 Matthew Leibowitz <mattleibowm...@gmail.com>:
> Hi all,
>
>
> I just want to see if anyone else has noticed that when loading images into
> memory, the exact same C# code uses more memory to hold the images (~1.5x
> the amount in Java).
>
> This Java code results in a total memory size of 105.5 MB:
>
> Bitmap[] bitmaps = new Bitmap[100];
>
> for (int i = 0; i < 100; i++)
> {
> String root =
> Environment.getExternalStorageDirectory().getAbsolutePath();
> String imagePath = "/evolution/threesixty/216/Edaphosaurus_001.jpg";
>
> bitmaps[i] = BitmapFactory.decodeFile(root + imagePath);
> }
>
> This C# code results in 148.1 MB:
>
> Bitmap[] bitmaps = new Bitmap[100];
>
> for (int i = 0; i < 100; i++)
> {
> string root = Environment.ExternalStorageDirectory.AbsolutePath;
> string imagePath = "/evolution/threesixty/216/Edaphosaurus_001.jpg";
>
> bitmaps[i] = BitmapFactory.DecodeFile(root + imagePath);
> }
>
> Does anyone have any ideas as to why? I understand that the .NET wrappers
> may use a little more to hold extra binding data or things, but surely not
> that much?
>
> Also, as a side question:
> Each image is only 60 KB on disk, why is the in-memory version 1 MB? I know
> that my loading method does not do any sampling/density checking, but that
> was not the aim. Surely loading a <100KB image should not exceed 100KB
> memory space?
>
>
> Regards,
> Matthew
>
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