Jonathan Pryor-2 wrote:
>
> On Aug 23, 2011, at 3:50 PM, chobo2 wrote:
>> // this seems to be how do it in android
>> ShapeDrawable bgShape = (ShapeDrawable )btn.getBackground();
>> bgShape.getPaint().setColor(Color.BLACK);
>>
>>
>> I tried
>>
>> ShapeDrawable bgShape = (ShapeDrawable)
>> Resources.GetDrawable(Resource.Drawable.danger_box);
>> bgShape.Paint.Color = Resource.Color.test;
>
> Those don't seem to be equivalent. :-)
>
> The "proper" equivalent would be:
>
> Button btn = GetSomeButton ();
> ShapeDrawable bgShape = (ShapeDrawable) btn.Background;
> bg.Paint.Color = Android.Graphics.Color.Black.ToArgb ();
>
> Note in particular that Color.BLACK is an `int`, but it's not a
> Resource-backed int, it's a packed RGBA `int`. (Such is the "joy" of
> `int`s...)
>
>> but it crashes on the first line(does not really seem to give a error).
>
> As for your crash on Resources.GetDrawable(), I don't know. Is there a
> stack trace printed in the Android Debug Log? (Try with 1.0.3 if
> possible.)
>
> Thanks,
> - Jon
>
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I guess I copied the wrong one I meant this one
ShapeDrawable sd = (ShapeDrawable)
getResources().getDrawable(R.drawable.color_box);
sd.getPaint().setColor(0x00000000);
Well What happens if I want to use a color from a resource file? Do I still
use the Resource and get's it's id?
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