Hi group,
I have no idea how to export images located outside of public directory.
Forgive me to disturbing groups such a lame questions but cant find
working example with google...
I have a route
$r->get('/pdataexport_qc')->to('Pdataexport#showQC');
$r->post('/showqcshowimg')->to('Pdataexport#showQCshowIMG');
in my Pdataexport.pm
sub showQC{
my $self = shift;
my $pDataPath = $self->config('phenotypeDataFromResoraDbFilesPath');
my $dir = $self->param('dir');
$self->stash( dirToQC => $dir);
$self->render('phenotypeExport/showDataQC');
}
my template phenotypeExport/showDataQC.html.ep
% layout 'all';
<table border="0" style="border-collapse: collapse;">
<tr><td><img
src="https://192.168.11.11:1777/showqcshowimg?dir=<%=$dirToQC%>&img=AH1vsAGE.png"></td></tr>
</table>
</body>
</html>
which generates me nice url
<table border="0" style="border-collapse: collapse;">
<tr><td><img src="https://
192.168.11.11:1777/showqcshowimg?dir=2018-04-03-18-32-46_G&img=AH1vsAGE.png">
</table>
</table>
but in log output I can see that was not routed to showqcshowimg
sub showQCshowIMG {
my $self = shift;
my $img = $self->param('img');
my $dir = $self->param('dir');
my $pDataPath = $self->config('phenotypeDataFromResoraDbFilesPath');
$self->render_file(filepath => $pDataPath.$dir."/".$img, 'filename' =>
$img );
}
Can you give a simpe example how it should be done?
or maybe you know page or open project which can play as example?
Thank you,
tj
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